Giannis Antetokounmpo Named 2019-20 NBA Defensive Player of the Year

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Bucks star Giannis Antetokounmpo, who is of Nigerian descent, has won the NBA Defensive Player of the Year award.

It is the first time Antetokounmpo, who finished in second place last season, has won the award.

Antetokounmpo beat Lakers’ Anthony Davies and Utah Jazz’ two-time winner of the award Rudy Gobert to win the prize.

Antetokounmpo, the 2018-19 NBA Most Valuable Player, becomes the fifth player selected as both the NBA MVP and the NBA Defensive Player of the Year in a career, joining Michael Jordan, Hakeem Olajuwon, David Robinson and Kevin Garnett.

The 25-year-old received 75 first-place votes from a global panel of 100 sportswriters and broadcasters and earned 432 total points.

Davies got 200 points and 14 first-place votes when Gobert got 187 points with six first-place votes.

In addition to being named the Defensive Player of the Year, Antetokounmpo is a finalist for the 2019-20 Most Valuable Player award after averaging 29.6 points, 13.7 rebounds and 5.8 assists in games played through March 11 while helping Milwaukee post an NBA-best 53-12 record during that period.

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